0=-16x^2+150

Solution for 0=-16x^2+150 equation:

0=-16x^2+150

We move all terms to the left:

0-(-16x^2+150)=0

We add all the numbers together, and all the variables

-(-16x^2+150)=0

We get rid of parentheses

16x^2-150=0

a = 16; b = 0; c = -150;
Δ = b2-4ac
Δ = 02-4·16·(-150)
Δ = 9600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{9600}=\sqrt{1600*6}=\sqrt{1600}*\sqrt{6}=40\sqrt{6}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-40\sqrt{6}}{2*16}=\frac{0-40\sqrt{6}}{32}
=-\frac{40\sqrt{6}}{32}
=-\frac{5\sqrt{6}}{4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+40\sqrt{6}}{2*16}=\frac{0+40\sqrt{6}}{32}
=\frac{40\sqrt{6}}{32}
=\frac{5\sqrt{6}}{4}
$